Question

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Answer 1

ok... so for a normal perfect square

\[(x - a)^2 = x^2 - 2ax + a^2\]

so looking at your quadratic its ugly, this is why.

when you look at the 1st term

\[\sqrt{2x^2} = \sqrt{2} x\]

Answer 2

as
\[(\sqrt{2}x)^2 = 2x^2\]

Answer 3

the normal process is that half the middle term squared is added to both sides...

so I'd divide every term by 2

and you get

\[x^2 - \frac{5}{2} x + ______ = 12 + _______\]

now find half the middle term = -5/4 now square it and add to both sides

so its

\[x^2 - \frac{5}{2} x + \frac{25}{16} = 6 + \frac{25}{16}\]

Answer 4

opps when dividing by 2 you get

\[x^2 - \frac{5}{2} x +~~~ = 6 + ~~~\]

Answer 5

the factored from is

\[(x - \frac{5}{4})^2 = 6 \frac{9}{16}\]

Answer 6

\(x^2 - \frac{5}{2} x + \frac{25}{16} = 6 + \frac{25}{16}
\\
2x^2 - 5 x + \frac{25}{8} = 12 + \frac{25}{8}\)

so you just add 25/8

Answer 7

did you get where 25/16 is coming from ?

Answer 8

so, you didn't get any of the above explanation ?

Answer 9

we take the co-efficient of x

which is -5/2 here

Answer 10

divide it by 2
so we get -5/4

Answer 11

then square it!
so 25/16

3 easy peasy steps :)

Answer 12

(-5/4)^2

Answer 13

(-5)^2 =25
4^2 =16

Answer 14

blank is same

but the answer is not 25.16

Answer 15

25/16***

Answer 16

as you can see, there is 2x^2 as the first term,
and not x^2

Answer 17

so we multiply both sides by 2

Answer 18

that gives us
25/16 *2 = 25/8
as the blank

Answer 19

64/9
but then you multiply 3 on both sides
so 64/3 is the blank :)

Answer 20

welcome ^_^

Answer 21

oh its 8/3

so
half of it is 4/3
square it, you get

16/9

multiply it by 3, you get 16/3 :P

Answer 22

yes

8/6 = 4/3

Answer 23

no, same

Answer 24

welcome ^_^