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Algebra
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Choose the correct answer that shows the base 10 number 23 in binary form.
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there are algorithms online, but 23 is between two powers of 2 , 2^5 < 23 <= 2^4
i dont get it @perl
a binary number is basically powers of 2 a1 *2^n + a2*2^n-2 + ... an , where an is either 0 or 1
10=1010 10+10=1010+1010=10100 10+10+3=10111
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2 | 23 ------ 2 | 11 R: 1 ------ 2 | 5 R: 1 ------ 2 | 2 R: 1 ------ 2 | 1 R: 0 ------ 1 R: 1 R is remainder at each stage of division. Write the remainders in a sequence from the last remainder to the first one: 10111
oh thats nice method i forgot
repeated division , and noting the remainders
upside down division is a nice touch
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