Question

Wires

Answer 1

b, is a light bulb or LED or any load.
Can the wires be connected to each other in a way that they could cancel their induced EMF?

The idea is somewhat inspired from the twisted pair concept of wiring.

Answer 2

@Jemurray3

Answer 3

No, because whatever the magnetic field does to one wire it will do to the other. Not reversed, or opposite, or whatever you like - exactly the same thing. If the right hand side of the first wire rises to a higher potential than the left hand side, then the same will be true of the second wire. It'd be essentially like having a single wire that's twice as thick.

Answer 4

I'm studying circuitry a lot, and I noticed one of these formulas:
\[I = \frac{ V _{1} - V _{2} }{ R _{1} - R _{2}}\] Where the current would flow in the higher potential different(V) and thought about this circuit:

Since they are in opposition they should cancel out, and current cannot flow. However, if one is to be higher than the other current will flow but reduced(similar to idea of back-emf). So I thought what if a magnetic field is in the center? Changing of course.

Answer 5

The magnetic field would induced "equal" PD's and should cancel each other out?

Answer 6

*IF* that is true, and I connected a load what would happen? Should "nothing" happen to it? It will not receive any power?

Answer 7

If everything is equal than yes, no current will flow. But you must realize how this is different from your original question, right? Because we're not asking whether current flows between the two wires, but rather if current flows in the whole circuit. If the two wires are present as you originally asked, but there is a larger external circuit that contains them both, then current certainly can flow around the larger circuit.

Answer 8

That does make sense, but why would current flow in a larger circuit?
See, what confuses me is that without the "load" they cancel out but with the load they increase current :P