(a+b)^2y^2-4aby-(a-b)^2 factorize.??
\[(a+b)^2 \cdot y^2 -4ab \cdot y -(a-b)^2 \\ A=(a+b)^2 \\ B=-4ab \\ C=-(a-b)^2 \\ \text{ where } Ay^2+By+C \\ A \cdot C =-(a+b)^2(a-b)^2 \text{ and again } B=-4ab \\ \text{ We want to find two factors of } -(a+b)^2(a-b)^2 \\ \text{ that have product } -(a+b)^2(a-b)^2 \\ \text{ and sum } -4ab \]
if that is possible..
We could probably cheat and used the quadratic formula and then go backwards from there.
But I want to see if we can think of the first way first
could you plz simplify it for me..!!
Oh I thought you wanted to factor it?
I don't if you want to factor or if you want to multiply it out (since you said simplify)
Factor is to write it as something*something
Can you please define simplify @abaham ?
http://www.wolframalpha.com/input/?i=factor+%28a%2Bb%29^2y^2-4aby-%28a-b%29^2+
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