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Mathematics 19 Online
OpenStudy (kamille):

The standard rolling dice is going to be rolled twice. What's the probability that the number of dots rolled at the second time will be greater than the one rolled at the first time?

OpenStudy (kamille):

@hartnn maybe you can have a look

OpenStudy (kamille):

they don't ask me the sum of it

OpenStudy (perl):

so you have ( x,y ) , count the number of dice where y > x

OpenStudy (perl):

i said google image of throwing two dice (not the sum )

OpenStudy (kamille):

the thing is, that they roll the dice once, the could get (1,2,3,4,5,6) and then they roll the same dice again (1,2,3,4,5,6) and they ask me what is the probality that the second time the dice will be rolled with a higher number than the first time?

OpenStudy (perl):

you should have a table of 6 rows and 6 columns

OpenStudy (perl):

36 in all

OpenStudy (kamille):

why?

OpenStudy (perl):

OpenStudy (kamille):

I find it a bit tricky, because first time they can roll,for example, 5,so the second time they must roll 6.. or if they roll 6 at the first time, then the probability is 0

OpenStudy (perl):

right, you need to look at the sample space of rolling to die , there are 36 possible outcomes

OpenStudy (perl):

rolling two dice*

OpenStudy (kamille):

okay, now i get, the answer is 15/36?

OpenStudy (kamille):

thanks

OpenStudy (perl):

|dw:1413625933019:dw|

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