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Mathematics 18 Online
OpenStudy (kamille):

Hey. There is a right triangle (I draw a sketch in comments), I need to find AD length (AB and AC were given)

OpenStudy (kamille):

OpenStudy (kamille):

@terenzreignz

OpenStudy (kamille):

I think I can use two ways of finding area, like: \[\frac{ AB*AC }{ 2}=\frac{ BC*AD }{ 2 }\] I can find BC from pythagoras theorem, am I thinking right?

ganeshie8 (ganeshie8):

that looks very much right and a nice idea indeed

OpenStudy (kamille):

thanks for checking this out;)

ganeshie8 (ganeshie8):

np :) you could also use similar triangles and setup a proportion which is more usual..

terenzreignz (terenzreignz):

That does work. I never would have thought of using area, I'd have gone for right triangle similarity. Way to think outside the box (or triangle haha)

ganeshie8 (ganeshie8):

either way you need to find the side BC first i guess

OpenStudy (kamille):

Uh,I was thinking about similarities but it made me a bit confused. How could I find it BD or DC anyways? they are not equal, right?

ganeshie8 (ganeshie8):

Once you have BC and AD, finding other sides becomes easy right ? if u feel uneasy about similar triangles, simply use pythagorean thm

ganeshie8 (ganeshie8):

Note that all the triangles we see in given diagram are right triangles

OpenStudy (kamille):

alright, thanks:)

ganeshie8 (ganeshie8):

use triangle ADB to solve BD : BD^2 + AD^2 = AB^2

ganeshie8 (ganeshie8):

use triangle ADC to solve DC : DC^2 + AD^2 = AC^2

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