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Mathematics 13 Online
OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

im stuck, plz explain?

hartnn (hartnn):

derivative of x^n is ?

OpenStudy (anonymous):

x?

hartnn (hartnn):

no i'm sure you've come across this formula : \(\Large \dfrac{d}{dx} x^n = n x^{n-1}\)

OpenStudy (anonymous):

oh yeah

hartnn (hartnn):

differentiate it one more time to get the 2nd derivative

OpenStudy (anonymous):

differentiate nx^n-1?

hartnn (hartnn):

yes

hartnn (hartnn):

is that a difficult task for ya ?

OpenStudy (anonymous):

Should we multiply it or not @hartnn

hartnn (hartnn):

not required

OpenStudy (anonymous):

Then product rule?

hartnn (hartnn):

nopes, we just find the co-efficient of x^4 term 12 times that will give you the co-efficient of x^2 term in f''(x) why ? that i am trying to explain her

OpenStudy (anonymous):

oh ok im trying to do it so chill @hartnn

OpenStudy (anonymous):

Oh I am getting you.. :)

OpenStudy (anonymous):

what do you mean coefficient of x^4

hartnn (hartnn):

if you multiply both terms in f(x), it will have all exponents from x^6 to constant, right ? so it will have a x^4 term too, isn't it ?

hartnn (hartnn):

for example if you multiply 3x^2 and (-6x^2) you will get -18 x^4 here, -18 is called the co-efficient of x^4

OpenStudy (anonymous):

but i dont get why i wouldnt multiply?

hartnn (hartnn):

you can, thats a longer method.

hartnn (hartnn):

if you want to, go ahead and multiply :) and tell me what did you get the co-efficient of x^4 as

OpenStudy (anonymous):

so muliplying the first two i would get 3x^5 right?

OpenStudy (anonymous):

id rather learn the shorter method ahahhaha

hartnn (hartnn):

why would u multiply x^3 and 3x^2 ?

OpenStudy (anonymous):

i thought thats what you said to do, ok nvm

hartnn (hartnn):

i asked for the 2nd derivative of x^n :P that too if you want to know why..

OpenStudy (anonymous):

how do i find the second derivative D;

hartnn (hartnn):

by differentiating the 1st derivative

hartnn (hartnn):

derivative of (n x^{n-1}) is ?

OpenStudy (tkhunny):

Did we find both pieces that lead to x^4?

hartnn (hartnn):

one, i found it for her, other was expecting she will find on her own

hartnn (hartnn):

clearly, your derivative skills are not upto the mark for attempting this question. please practice as many derivatives questions as you can...!

OpenStudy (tkhunny):

Fair enough. Just wondering if it was headed that way. :-)

OpenStudy (anonymous):

thanks lol @hartnn

hartnn (hartnn):

let me start asking simple questions what is derivative of x^2 can u find ?

OpenStudy (anonymous):

She can tell, I bet..!! :P

hartnn (hartnn):

you taught her ? ;)

OpenStudy (anonymous):

nx^n-1 (:

hartnn (hartnn):

thats for x^n i asked for x^2

OpenStudy (anonymous):

I said "Can", but she won't.. :P

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

He he he.. you saw?? :P

hartnn (hartnn):

i suspect you gave her the answer in a private message :P

OpenStudy (anonymous):

@waterineyes can you please leave

OpenStudy (anonymous):

are you calling me stupid?

hartnn (hartnn):

no one is calling you anything

OpenStudy (anonymous):

@mondona it is always the case that you hate me??

hartnn (hartnn):

@mondona moving ahead can you tell me the derivative of x^4 ??

OpenStudy (anonymous):

Why are you not saying anything to hartnn, he blamed me and you for having answer through private message.. :P

OpenStudy (anonymous):

4 (x^3)

OpenStudy (anonymous):

Go ahead, I am leaving.. :)

OpenStudy (anonymous):

thank you

hartnn (hartnn):

now can you tell me the derivative of 4x^3 ?

OpenStudy (anonymous):

3(4x^2)

hartnn (hartnn):

4 (3x^2) yes which is 12x^2, right ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

so the derivative of x^4 = 4x^3 derivative of 4x^3 = 12x^2 so derivative of derivative of x^4 is 12x^2 means 2nd derivative of x^4 is 12 x^2 makes sense ?

OpenStudy (anonymous):

so the answer my question is looking for is 12x^2?

OpenStudy (anonymous):

its just asking for the 2nd derivative?

OpenStudy (tkhunny):

Why would the 2nd derivative of x^4 be the answer to your question? You need the x^4 term in your original expression, not an example problem.

OpenStudy (anonymous):

oh so just 12

hartnn (hartnn):

i did all that so that you know why we need to multiply the co-efficient of x^4 by 12 :P question asked for co-efficient of x^2 it will be 12 times the co-efficient of x^4 why ? because 2nd derivative of x^4 is 12x^2

OpenStudy (anonymous):

i get confused when 5 people start coming in lol

OpenStudy (anonymous):

so what is @tkhunny talking about

OpenStudy (tkhunny):

You are still missing the "in your original expression" part. Do NOT use the example problem to answer your question.

OpenStudy (anonymous):

hartnn (hartnn):

"co-efficient of x^2 will be 12 times the co-efficient of x^4" did you get this part ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

if so, just find the co-efficient of x^4 for f(x)

OpenStudy (anonymous):

of nx^n-1 is ^

OpenStudy (anonymous):

n(nx^-1)

OpenStudy (anonymous):

this is honestly taking much more time than it should lol idk what youre saying

OpenStudy (anonymous):

derivative of nx^n-1 is n(nx^-1)

hartnn (hartnn):

we are past that find f(x)

hartnn (hartnn):

(x^3 +3x^2 +3) (3x^3 - 6x^2 -8x+1) = ... ?

OpenStudy (anonymous):

SO NOW YOURE TELLING ME TO SOLVE IT?! you told me not to earlier!!!!!

OpenStudy (anonymous):

@tkhunny can you please help me

hartnn (hartnn):

thats the longer way , remember ? i don't think you'll get the shorter way

OpenStudy (anonymous):

so what were we talking about earlier? was that just wasting my time??

hartnn (hartnn):

as already told, that was to explain why are we finding the co-efficient of x^4 and why we will multiply it by 12

OpenStudy (anonymous):

3-24 x-15 x^2-14 x^3-26 x^4+3 x^5+3 x^6

OpenStudy (anonymous):

now what

hartnn (hartnn):

correct, so whats the co-efficient of x^4 from there ?

OpenStudy (tkhunny):

Whoa! Settle down, there. Unique answers don't care how you find them. There may be several ways to proceed. In my opinion, hartnn's original way was BY FAR the best way. However, you didn't seem to be getting it. It would have been great if you had been getting it. So, this is where we are... 1) Let's just multiply out the entire expression. 2) When you gnerate all nine pieces of the multiplication, look at the two pieces that contributed to x^4. 3) Stop and think a little about how we might have found those two pieces without multiplying the entire expressions. 4) In any case, once we have the WHOLE of the x^4 term, the 2nd derivative shoudl be no problem, using the usual polynomial rule.

hartnn (hartnn):

*12 pieces

OpenStudy (tkhunny):

Whoops! 12 pieces.

hartnn (hartnn):

you there ? you're just one step away from the answer...

OpenStudy (anonymous):

sorry idk why openstudy keeps on disconnecting

hartnn (hartnn):

the co-efficient of x^4 from that 3-24 x-15 x^2-14 x^3-26 x^4+3 x^5+3 x^6 is ?

OpenStudy (anonymous):

-26

OpenStudy (anonymous):

right?

hartnn (hartnn):

yes now just multiply it by 12 and done!

OpenStudy (anonymous):

wait is it 26 or -26?

OpenStudy (anonymous):

i think i messed up

OpenStudy (anonymous):

312

hartnn (hartnn):

-26

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