Question

question in the pic

Answer 1

It's physics, sorry but I don't know how to do that
have you tried asking in the physics section?
and if anything, you can tag hartnn, hartnn is really smart

Answer 2

np

Answer 3

@hartnn

Answer 4

you know how to combine series and parallel resistances?

Answer 5

yup i know...and i know how to solve this but i just couldn't get the right answer

Answer 6

plz solve this for me...i need to check what i'm doing wrong

Answer 7

would the resistance from A to B be the total resistance of the system? or am i having a bad thought ...

Answer 8

i see no voltage in the systen

Answer 9

please show your work and we will find the error

Answer 10

yes
R_AB is total resistance of the system and its given to be 65

Answer 11

@hartnn its difficult to write on this just gimme the solution plz

Answer 12

you can write in statements

like
"i did 120 || 40 and i got ..."

Answer 13

i got the answer 39.something but the actual one is 46.somthing

Answer 14

we have 3 parallels .... recently started learning this stuff myself

Answer 15

okay!
i will guide you through the process

first find

120 || 40
because 120 and 40 are in parallel
what do u get ?

Answer 16

i did this (120 || 40 || R + 5) + R

Answer 17

thats correct

Answer 18

be careful with brackets
its
(120 || 40 || (R + 5)) + R

Answer 19

if thats correct than y i'm not getting the right answer

Answer 20

lets go step by step

120 || 40 is ??

Answer 21

i dont feel like going step by step...coz i've sooooo much to study sooooooo little time...just solve this i'll check my mistakes

Answer 22

*i've got

Answer 23

in that case, i can't help you, sorry buddy :)

Answer 24

can we do the parallel in one shot?\[\frac1{R_p}=\frac1{R_1}+\frac1{R_2}+\frac1{R_3}+...\]
or do we have to split it into parts?

Answer 25

@hartnn yar ab tu aesa kare ga?

Answer 26

both ways work fine amistre

Answer 27

then calculate 120 || 40
it doesn't take more than 10 seconds :P

Answer 28

4/120

Answer 29

ahhh forget it i'll ask someone else other than this site...this site never helped me

Answer 30

right, we're helpful to only those who want to learn :)

Answer 31

u have a wrong thinking of who wants to learn and who doesn't

Answer 32

do you want to learn ?

Answer 33

i do but what i'm asking u can u do it or not?

Answer 34

so lets continue
what did u say
120 ||40 = ... ?

Answer 35

yes or no?

Answer 36

bye bye

Answer 37

your wish :)

Answer 38

@CO_oLBoY If you are going to post a question, expect to recieve the help you need. Learn manners before you post a next one because that was just rude.

Answer 39

i did the que myself...thank you all for NOT helping me