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Discrete Math
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Find f(1), f(2), f(3), and f(4) if f(n) is defined recursively by f(0) = 1 and for n = 0,1,2,... a) f(n+1) = f(n) + 2 b) f(n+1) = 3 f(n)
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f(n+1) what value of n we should take so that we get f(1) f(n+1)=f(1)??? at what value on n
what we put in place of n in f(n+1) so that it become f(1)??
yeah you are right
so now f(n+1)=f(n)+1 for n=0 f(1)=f(0)+1 =????
plug in value of f(0)
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f(1) = f(0) + 1 = 1 f(1)?
f(0)=1 f(1)=1+1=2 similarly find others
The answers in the back of textbook: f (1) = 3, f (2) = 5, f (3) = 7, f (4) = 9 so f(1) is 3 not 2..
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