Question

What is the maximum velocity (in m/s) acquired by an alpha particle when accelerated between two plates with a potential difference of 580.0 volts?
Note: An alpha particle is essentially the nucleus of a helium atom - 2 protons and 2 neutrons.

Answer 1

I think you can use the formula: \(\sf \color{blue}{\frac{kQ}{r^2}}\) where "k" is the constant: \(\sf 9.0 \times 10^9 \frac{N~ m^2}{C^2}\)

Answer 2

I need a step by step process to help me with this question. Thank you.