Question

help derivatives

Answer 1

so, firstly, how you can rewrite \[\sqrt[n]{a}\]

Answer 2

uh? if \[\sqrt[n]{a}=a ^{\frac{ 1 }{ 2}}\], then

\[\sqrt{\sin(4x)}=?\]

Answer 3

thats what i got, i cant put the square root here so i screenshotted

Answer 4

oh wait the 2 goes on the bottom right?

Answer 5

uh, I believe it should be

\[f'(x)=(\sqrt{\sin4x})'=((\sin4x)^{\frac{ 1 }{ 2 }})'=\frac{ 1 }{ 2 }(\cos4x)^{\frac{ -1 }{ 2 }}=\frac{ 1 }{ 2*(\cos4x)^{2} }\]

Answer 6

but @hartnn could you have a look at this,please?

Answer 7

chain rule