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derivatives
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@gorv help!!
@gorv
what is derivative of ln x??
@mondona
@ganeshie8
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1
The Chain Rule dy/dx = dy/du *du/dx let u= (1-2x) then use the rule above....
i got 1/(1-2x)^2 thank you(:
thats right, right?
Not sure where you got your exponent from...
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doesn't look right to me - haven't done th esum - but ther is prolly a 2* something in there from du/dx
^Indeed there will be a "times" 2 because you need to take the derivative of the inside function as well
\[\frac{d}{du} \ln u = \frac{1}{u}\] \[\frac{d}{dx} (1-2x) = -2\]
ohh so it would be 1-2x sorry!
1/1-2*
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1/1-2x* lol my bad
slow down - do the process methodically
@dumbcow has given you nearly all you need
\[\frac{dy}{dx} = \frac{1}{u}* (-2) = \frac{-2}{1-2x}\]
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