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Mathematics 7 Online
OpenStudy (pixiedust1):

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OpenStudy (anonymous):

Hello..

OpenStudy (anonymous):

What are you trying to find?

OpenStudy (amistre64):

complete the square?

OpenStudy (anonymous):

I am here for the same.. :)

OpenStudy (pixiedust1):

I am interested in learning the concept, because I got an entire page of these

OpenStudy (amistre64):

divide off the 3 and you have a 'usual' looking setup

OpenStudy (anonymous):

Amistre is well experienced than me, If I am not allowing him to teach you, then I am spoiling your future.. :P

OpenStudy (amistre64):

now the key is in understanding what a complete square looks like to start with (x+n)^2 is a perfect square ... what do we get when we expand it?

OpenStudy (amistre64):

(x+n)(x+n) = x^2 + 2nx + n^2

OpenStudy (amistre64):

when we compare a perfect square to some trinomial ... x^2 + bx + c = x^2 +2n x + n^2 2n = b, giving us n = b/2 right?

OpenStudy (amistre64):

the number to add therefore is n^2 = (b/2)^2

OpenStudy (amistre64):

3x^2 + 8x + __ = -1 + ____ 3(x^2 + 8/3 x + __) = -1 + ____ n = (8/3)/2 lets add/subtract in [(8/3)/2]^2 3(x^2 + 8/3 x + (8/6)^2 - (8/6)^2) = -1 + ____

OpenStudy (amistre64):

.. you said you understood so far ...

OpenStudy (amistre64):

(x+n)(x+n) = x^2 + 2nx + n^2 when we compare a perfect square to some trinomial ... x^2 + bx + c = x^2 +2n x + n^2 2n = b, giving us n = b/2

OpenStudy (amistre64):

since your case gives us b=8/3 ... what do we determine?

OpenStudy (amistre64):

that fine as well :)

OpenStudy (amistre64):

now we need to add/subtract n^2 to 'complete the square'

OpenStudy (amistre64):

x^2 + bx + c +n^2 - n^2 (x+n)^2 + c - n^2

OpenStudy (amistre64):

this is a process yes

OpenStudy (amistre64):

to apply it 3((x+4/3)^2 - (4/3)^2) = -1 + ______ 3(x+4/3)^2 - 3(4/3)^2 = -1 + ______ 3(x+4/3)^2 - 16/3 = -1 + ______ 3(x+4/3)^2 -13/3 - 3/3 = -1 + ______ 3(x+4/3)^2 -13/3 = ______ but thats all i can make of this really

OpenStudy (amistre64):

it may help to detemrine how i need to go with it yes

OpenStudy (amistre64):

ok, now im wondering what the quesiton is asking for ... can you provide a picture of it to eliminate any loss in translation

OpenStudy (amistre64):

are the blanks on the left and the right spose to be the same value?

OpenStudy (amistre64):

then yeah, draw it out the best you can

OpenStudy (amistre64):

good luck

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