how to find the domain and range of f(x)=ln(x+sqrt x^2+1 )
@undeadknight26

Question

zzr0ck3r · Answer

is it $\log(x+\sqrt{x^2}+1)$?

zzr0ck3r · Answer

if so then $x+\sqrt{x^2}+1>0$ which is always true. Why?

hartnn · Answer

unlikely that would be the question....
$\log(x+\sqrt{x^2+1})$
or 
most likely 
$\log(x)+\sqrt{x^2+1}$

zzr0ck3r · Answer

press enter already

zzr0ck3r · Answer

:P

hartnn · Answer

Tab + Enter

anonymous · Answer

but i cant understand on this math and here question

zzr0ck3r · Answer

what does tab + enter do?

hartnn · Answer

it posts

zzr0ck3r · Answer

o lol I see, I am tab+space bar

hartnn · Answer

that F, my dear, is not an odd function!

zzr0ck3r · Answer

we still need to know where that second bracket is.

hartnn · Answer

none of the 3 Fs we discussed are odd functions

anonymous · Answer

ummm oh but did you get understand this q or no ?

zzr0ck3r · Answer

no we don't know what the question is because you only have one (, we need you to close it )

example

f(x) = 3x+2 is completely different than 3(x+2)

so until you add that second parentheses we don't know what you are asking. we can only assume, and that is not safe in maths

hartnn · Answer

nopes, the question is not clear

anonymous · Answer

its not ( on last and its 1

anonymous · Answer

i edited on here  (: ,,

zzr0ck3r · Answer

still not clear if you mean $\sqrt{x^2+1}$ or $\sqrt{x^2}+1$

hartnn · Answer

i am quite sure its the 1st
only then , F will be odd function

anonymous · Answer

okay.. do you know calculus ?

hartnn · Answer

yes

anonymous · Answer

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