How many moles of glucose (C6H12O6) are in 4.0 liters of a 4.5 M C6H12O6 solution? 18 moles 12.5 moles 8.5 moles 1.1 moles
Hello @HollidayT and welcome to \(\LARGE \sf \bbox[#40B9E9]{\color{white}{Open}}\bbox[#A8CE91]{\color{white}{Study}}\) In order to solve this problem we are going to be looking at the definition of molarity. We define the molarity as:\[\Large C=\frac{ n }{ V }\]Here is \(C\) the molarity in \(\sf mol ~ L^{-1}\), this unit is also known as molar \(\sf M\). \(n\) is the amount of substance in \(\sf mol\), and \(V\) is the volume in \(\sf L\). In this question we want to find out the amount of substance, \(n\), in a glucose solution with a concentration of 4.5 \(\sf M\) with a volume on 4.0 \(\sf L\). So to solve the problems we solve for the amount of substance \(n\) in the equation first written:\[\Large n=C \times V\]Insert the numbers into the equation above and find the amount of stance \(n\). Answer is found in the link below but it is suggested you calculate your self. http://bit.ly/1qQWXVS
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