Find the exact real value of arccosThe quantity square root of two divided by two
find a number \(x\) where \(\cos(x)=\frac{\sqrt2}{2}\) it should ring a bell
pi over 4?
yes
Thank you so much (:
do you know how i can do this Use a calculator to find the approximate value of cos-1(0.55)
yw make sure when you solve these that you pick the right number in the right range
depends on the calculator i haven't used one since 2004 just use this http://www.wolframalpha.com/input/?i=arccos%28.55%29 gives answer in both radians and degrees
I got it ! I just had to type the exact thing on my calculator , and for the first question I asked now its asking me for the exact real value of across The quantity square root of two divided by two , is that one across the actual cos on the unit circle?
yes
for arccosine pick the ones on the upper half of the unit circle, i.e. between \(0\) and \(\pi\) for sine pick on the right between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\)
so is it 11pi over 6 or 7 pi over 4 ? for the cos inverse of root 2 over two ?
oh no you had it right the first time just \(\frac{\pi}{4}\)
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