Question

Find the absolute extrema of the function on the closed interval.
y=3x^(2/3)-2x [-1, 1]
minimum (x,y)=
maximum (x, y)=
My work so far
f(1)=3(1)^(2/3)-2(1)=1
f(-1)=3(-1)^(2/3)-2(-1)=5
at max: (1,1) and (-1,5)
and that was wrong and not quit sure about the min i think i really need to see an example

Answer 1

minimum occurs at (0,0)

Answer 2

it says my max is wrong too

Answer 3

your max is correct

Answer 4

i checked it out on my graphic calculator
theres a max at (1,1)