5^X+2 = 10(8^2X-2)
quick question... is it 1. \[5^{x + 2} = 10(8^{2x - 2})\]
or simply 2. \[5^x + 2 = 10(8^{2x} - 2)\]
5^X+2 = 10(82X-2) 5^X+2 = 820X-20 5^X = 820X-20-2 5^X = 820X-22 ln (5^X) = ln 820X- ln 22 X (1.6) = ln 820X - (3.091) 1.6X = ln 820X - 3.091 e^(1.6X + 3.091) = 820X e^1.6X e^3.091 = 820X
http://www.wolframalpha.com/input/?i=%28e^%281.6X%29%29*%28e^3.091%29+%3D+820X+
@gerryliyana I think there are a few holes in your solution \[10\times8^{2} \neq820\] just looking at a simple error
ahh i was typo and wrong
I though 82X not 8^2X,
and it's a bit hard to answer the question without the correct version of the equation
If 5^X+2 = 10(8^2X-2), then 5^X+2 = 10(8^2X-2) 5^X+2 = 10*8^2X-20 5^X = 10*8^2X-20 -2 5^X = 10*8^2X-22 ln(5^X) = ln(10*8^2X)- ln(22) X ln 5 = ln 10 + ln (8^2X) - ln 22 X ln 5 = ln 10 + 2X ln 8 - ln 22 X ln 5 - 2X ln 8 = ln 10 - ln 22 X (ln 5 - 2 ln 8) = ln 10 - ln 22 X = (ln 10 - ln 22)/(ln 5 - 2 ln 8)
\[X = \frac{ \ln 10 - \ln 22 }{ \ln 5 - 2*\ln 8 } \]
X = 0.30926625501
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