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Mathematics 11 Online
OpenStudy (anonymous):

5^X+2 = 10(8^2X-2)

OpenStudy (campbell_st):

quick question... is it 1. \[5^{x + 2} = 10(8^{2x - 2})\]

OpenStudy (campbell_st):

or simply 2. \[5^x + 2 = 10(8^{2x} - 2)\]

OpenStudy (anonymous):

5^X+2 = 10(82X-2) 5^X+2 = 820X-20 5^X = 820X-20-2 5^X = 820X-22 ln (5^X) = ln 820X- ln 22 X (1.6) = ln 820X - (3.091) 1.6X = ln 820X - 3.091 e^(1.6X + 3.091) = 820X e^1.6X e^3.091 = 820X

OpenStudy (campbell_st):

@gerryliyana I think there are a few holes in your solution \[10\times8^{2} \neq820\] just looking at a simple error

OpenStudy (anonymous):

ahh i was typo and wrong

OpenStudy (anonymous):

I though 82X not 8^2X,

OpenStudy (campbell_st):

and it's a bit hard to answer the question without the correct version of the equation

OpenStudy (anonymous):

If 5^X+2 = 10(8^2X-2), then 5^X+2 = 10(8^2X-2) 5^X+2 = 10*8^2X-20 5^X = 10*8^2X-20 -2 5^X = 10*8^2X-22 ln(5^X) = ln(10*8^2X)- ln(22) X ln 5 = ln 10 + ln (8^2X) - ln 22 X ln 5 = ln 10 + 2X ln 8 - ln 22 X ln 5 - 2X ln 8 = ln 10 - ln 22 X (ln 5 - 2 ln 8) = ln 10 - ln 22 X = (ln 10 - ln 22)/(ln 5 - 2 ln 8)

OpenStudy (anonymous):

\[X = \frac{ \ln 10 - \ln 22 }{ \ln 5 - 2*\ln 8 } \]

OpenStudy (anonymous):

X = 0.30926625501

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