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i need help in partial differentiation problems
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\[if u =\frac{ \tan^{-1} (xy) }{ \sqrt{1+x ^{2}+ y^{2}} }\]
Show that \[\frac{ \delta u }{ \delta x} =\frac{ y }{ (1+x^{2})\sqrt{1+x ^{2}+y ^{2}} }\]
when partially diff. with respect to x, we treat 'y' as constant
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did you try ?
@perl yes...
@hartnn yes..
Whenever there is dy/dx, that shall become 0.
Treat 'y' as a constant. Now apply normal differentiation. d(u/v)/dx= ((v.du/dx)-(u.dv/dx))/v^2 Here, u=arctan(xy), v=(1+x^2+y^2)^0.5
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it will b like differentiating \(\Large u =\frac{ \tan^{-1} (ay) }{ \sqrt{b+x ^{2}} }\) where a and b are constants
*** \(\Large u =\frac{ \tan^{-1} (ax) }{ \sqrt{b+x ^{2}} }\)
|dw:1413719011727:dw|
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