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Mathematics 9 Online
OpenStudy (kj4uts):

Fill in the blank. In the triangle below, y=__. Round your answer to two decimal places. Please explain, thank you.

OpenStudy (kj4uts):

OpenStudy (anonymous):

What side of the triangle is Y ?

OpenStudy (kj4uts):

did you see the attachment

OpenStudy (anonymous):

Yes i m asking you like the name of the side

OpenStudy (anonymous):

|dw:1413736128032:dw|

OpenStudy (kj4uts):

oh ok so hypotenuse then

OpenStudy (anonymous):

Yup! Okay now we use the Pythagorean theorem

OpenStudy (anonymous):

a^2+b^2=c^2

OpenStudy (kj4uts):

so do we fill in the information we already have into this formula

OpenStudy (anonymous):

i think i made a mistake . We dont use the theorem we use Sine

OpenStudy (anonymous):

Do you have a calculator ?

OpenStudy (kj4uts):

yes

OpenStudy (anonymous):

|dw:1413736596952:dw|

OpenStudy (anonymous):

We know one angle measure beside 90 . That angle is 52

OpenStudy (anonymous):

So type 52 then hit sine

OpenStudy (kj4uts):

sin(52) = 0.788010754

OpenStudy (anonymous):

I got 0.98662759204

OpenStudy (kj4uts):

oh ok im not sure why i got that i pressed sin(52) and got 0.788

OpenStudy (anonymous):

I think your right though

OpenStudy (kj4uts):

yeah i checked online it is

OpenStudy (anonymous):

Yup i tried it on another calculator your right :)

OpenStudy (anonymous):

Sine = opposite / hypotenuse

OpenStudy (anonymous):

Plug our values into that

OpenStudy (kj4uts):

the opposite is 35 but the hypotenuse is y on the picture

OpenStudy (anonymous):

0.788010754 = 35/y

OpenStudy (kj4uts):

im still confused about the y part what is y?

OpenStudy (anonymous):

In your picture the hyotenuse was labeled Y

OpenStudy (kj4uts):

yeah but on the formula Sine = opposite / hypotenuse or 0.788010754 = 35/y don't you need to plug in something for y to solve

OpenStudy (anonymous):

We dont have the value of y . Were using that equation to find the value of y

OpenStudy (kj4uts):

oh ok

OpenStudy (anonymous):

So now what do you get ?

OpenStudy (kj4uts):

y=35/sin(38°)=56.85

OpenStudy (anonymous):

Where did sin 38 come from

OpenStudy (kj4uts):

the 38 degrees is a result of 180°-52-90=38 being that a triangle is 180 degrees I subtracted 52 and 90

OpenStudy (anonymous):

You dont do sine again . Just do regular algebra to find y in the equation 0.788010754 = 35/y

OpenStudy (anonymous):

I got 44.42

OpenStudy (anonymous):

@dumbcow @jim_thompson5910 Could you check this please ?

OpenStudy (dumbcow):

hmm i think you should have used cos instead of sin the 35 is adjacent to angle 52

OpenStudy (kj4uts):

I just right now found that website above

OpenStudy (dumbcow):

or do what @KJ4UTS did and use angle 38 :)

OpenStudy (dumbcow):

\[\sin 38 = \cos 52 = \frac{35}{y}\] \[y = \frac{35}{\sin 38} = \frac{35}{\cos 52}\]

OpenStudy (kj4uts):

i got 56.84942359 for both and if it says round two decimal places I guess that makes the answer 56.85 i think?

OpenStudy (anonymous):

Yes rounded its 56.85

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