Question

lim e^-x_ x approaches - infinity

Answer 1

what have you tried?
where are you confused?

Answer 2

try rewriting \(e^{-x}\) as a fraction

Answer 3

do you know what \(e^x\) goes to as x goes to infinity?

Answer 4

it goes to 0

Answer 5

why would \(e^x\to0\) as \(x\to \infty\)
?

Answer 6

\(e^x\text{, or } e^{-x}\) goes to 0?

Answer 7

\(e^{-x}\) is a different story, because that uses a reciprocating exponent

Answer 8

it reduces e^x as x increases

Answer 9

\(\lim _{x \rightarrow \infty} e^x=\infty\)

Answer 10

sorry rather increases

Answer 11

\[\lim_{x \rightarrow \infty}e^{-x}=\lim_{x \rightarrow \infty}\frac{ 1 }{e^{x} }\]

Answer 12

limx→-∞e−x

Answer 13

how would it get negative?

Answer 14

that is the question given

Answer 15

the answer is positive infinity. but i dont know how

Answer 16

oh... sorry. i see now. you have

\[\lim_{x \rightarrow -\infty} e^{-x} = \lim_{x \rightarrow \infty} e^x\]

Answer 17

it goes to infinty because \[\lim_{x \rightarrow -\infty}e^x=0\]
so\[\lim_{x \rightarrow -\infty}e^{-x}= \lim_{x \rightarrow -\infty}\left(e^{x} \right)^{-1}=\left( \lim_{x \rightarrow -\infty}e^{x} \right)^{-1}\]

Answer 18

sorry for the confusion

Answer 19

thank you, i appreciate that