Question

sinx+2cos(2y)=1 implicit differentiation ?

Answer 1

We have to derive everything and then solve for y'

Answer 2

which is
cosx (-4sin(2y))y' = 0

Answer 3

And we put y' wherever we integral with respect to y....

So we now solve for y'

(-4sin(2y))y' = -cosx

Answer 4

y' = (1/4)(cosx/sin(2y)

Answer 5

What happen to add operation between sin(x) and 2cos(2y)?

Answer 6

(u+v)'=u'+v'
not u'v'

Answer 7

\[\cos(x)-4\sin(2y) \cdot y'=0 \text{ try silving this for } y'\]

Answer 8

And you still get the same thing as what master got somehow.