Ask your own question, for FREE!
Mathematics 15 Online
TheSmartOne (thesmartone):

I will post the question below... Math question...

TheSmartOne (thesmartone):

If \(a _{k}=5+5^2+5^3+5^4+.....5^k\) for which of the following values of k will \(a _{k}\) be divisible by 10?

TheSmartOne (thesmartone):

A) 35 B)51 C)75 D)88 E)91

OpenStudy (anonymous):

i would look for a pattern

OpenStudy (anonymous):

i can make a guess, my guess is that k has to be even, but i could be wrong look for a pattern and see

TheSmartOne (thesmartone):

@satellite73 The answer is 88... and that is the only even answer choice..

TheSmartOne (thesmartone):

BTW this is not a homework or test question...

TheSmartOne (thesmartone):

I just wanted to know how to solve it if I ever encounter a problem like it...

TheSmartOne (thesmartone):

The question is supposed to be a level 5 Number Theory question...

geerky42 (geerky42):

\[x+x^2+x^3+\cdots+x^n=\sum_{k=1}^nx^k = \dfrac{x^{n+1}-1}{x-1}\] Check here: http://mikestoolbox.com/powersum.html

geerky42 (geerky42):

Maybe that helps?

TheSmartOne (thesmartone):

Yes...

OpenStudy (akashdeepdeb):

Find the sum: Geometric progression = \[\frac{5}{4} (5^k-1)\] For this to be divisible by 10, \[\frac{5^k-1}{4} ~~must~~be~~even!\] \[\frac{5^k-1}{4} = 2n\] [n is an integer] \[5^k = 8n + 1\] Find what k is.

geerky42 (geerky42):

I take that as no, since it seem obvious to you.

OpenStudy (akashdeepdeb):

Only the even 'k's will be correct. But this proof is very crude. There are better ways with Number Theory, probably with mod, but I am not proficient in Number Theory.

TheSmartOne (thesmartone):

Well my teacher explained it just like but I wasn't sure.. But now you guys clarified it.. ^_^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!