Question

find the slope of the tangent line to the polar curve r=7/theta at theta=pi

Answer 1

Use this formula
\[\frac{ dy }{ dx }=\frac{ \frac{ dr }{ d \theta } }{\frac{ dr }{ d \theta } }\]
with you numerator multiplied by \[\sin \theta+r \cos \theta \]
and your numerator multiplied by \[\cos \theta-r \sin \theta \]
After you have found you \[\frac{ dy }{ dx }\] then you will need to substitute your \[\theta=\Pi \]

Answer 2

Do you get what I am trying to show you?

Answer 3

If you don't go to google and search for this following link
http://tutorial.math.lamar.edu/Classes/CalcII/PolarTangents.aspx

Answer 4

I understand what you are saying. my only issue is what exactly do i use as x and y ?

Answer 5

you need not to worry about x and y..... .in this case \[M=\frac{ dy }{ dx } slope\]
You will first need to derive the given r in terms of \[\frac{ dr }{ d \theta }\]
and then just plug in that in the formula that I gave you
substitute everything as it .... for example where there is r just plug it in and where there is Theta just plug it in and get your Tangent slope