Question

(a^2b^2)^2 explain.

Answer 1

\[(a^2b^2)^2=(a^2b^2)(a^2b^2) = a^2a^2b^2b^2 = a^{2+2}b^{2+2}=\boxed{a^4b^4}\]
Shortcut: You can "distribute" exponent like this:
\((a^2b^2)^2 = (a^2)^2(b^2)^2 = a^{2\cdot2}b^{2\cdot2} = \boxed{a^4b^4}\)

Answer 2

oh that makes a lot of sense but will take a while to remember

Answer 3

(a^3b^2)^3? so i do 3x2? then 3x3 so it would end out as a^6 b^9?

Answer 4

lol that was easy :)

Answer 5

wait it said it was wrong

Answer 6

(x^2y^3)^2 ??

Answer 7

i think i know how to do it i just need help explaining the steps

Answer 8

\[\large
(a^m)^n = a^{m*n}
\]

Answer 9

$$\Huge (a^m)^n =a^{m\cdot n}$$

Answer 10

so then it would be 2x3 which is 6? cause they both equal 6

Answer 11

or does one eqaul 4? i mean like is an answer in the problem a 4? or are they both 6?

Answer 12

caue im confused about if i multiply 2 and 2

Answer 13

\[\large
(a^3b^2)^3 = (a^3 \times b^2)^3 = (a^3)^3 \times (b^2)^3 = ?
\]

Answer 14

a^9 x b^6 which would be ab^15?

Answer 15

to find the power of a power you multiply the exponents

Answer 16

\[\large a^9b^6\]
But you cannot add 9 and 6 because the bases are different.

Answer 17

9x6=54 lol

Answer 18

nope

Answer 19

slow down, and think about what you are doing

Answer 20

well aum said not to add so i multiply right?

Answer 21

what about the base?

Answer 22

\[\large
a^9 \times a^6 = a^{9+6} = a^{15} \\ \large
a^9 \times b^6 =a^9b^6 \\ \large
(a^9)^6 = a^{9\times6} = a^{54} \\ \large
\]

Answer 23

ohhh okay

Answer 24

@TheSmartOne they keep coming on this question

Answer 25

@aum i only have x and y so which letter do i use?

Answer 26

@Data_LG2

Answer 27

\[\large
(x^2y^3)^2 = (x^2)^2 \times (y^3)^2 = x^4y^6
\]

Answer 28

so i put that?

Answer 29

lol i need help

Answer 30

so its x^4y^6?

Answer 31

yes