What three lengths can NOT be the lengths of the sides of a triangle? a) 23 m, 17, m,14 m or b)11 m, 11 m, 12 m or c) 5 m, 7 m, 8 m or d) 21 m, 6 m, 10 m
Take each set of lengths and take two lengths at a time and add them together. If in one choice, any two lengths added together is not greater than the third length, that cannot be a triangle.
I did that I still can't find the answer
For example, here are two sets of lengths: 1) 13 cm, 12 cm, 18 cm 2) 5 in., 8 in., 15 in. Let's work with set 1) First, add each set of two lengths and compare to the third length. a. 13 cm + 12 cm = 25 cm > 18 cm (ok) b. 12 cm + 18 cm = 30 cm > 13 cm (ok) c. 13 cm + 18 cm = 31 cm > 12 cm (ok) Since each two lengths added together are greater than the third side, 13 cm, 12 cm, 18 cm can be a triangle.
they're all greater
No they are not. Now let's do example 2). a. 5 in. + 8 in. = 13 in. < 15 in. (not ok) Just from that comparison, you can tell that set 2) will not make a triangle.
I see
You need to do one set at a time. Each set may need 3 additions and comparisons.
Here is your first choice: a) 23 m, 17 m,14 m What is 23 m + 17 m? Compare to 14 m What is 17 m + 14 m? Compare to 23 m What is 23 m + 14 m? Compare to 17 m
1. 40m 2. 31m 3. 37m
a) 23 m, 17 m,14 m 23m + 17 m = 40 m > 14 m (ok) 17 m + 14 m = 31 m > 23 m (ok) 23 m + 14 m = 37 m > 17 m (ok) Choice a) makes a triangle. Now do the same to choices b), c), and d).
I'm so confused
You are correct. Now see that for each sum of two sides, I compared with the third side. Each sum was greater that the third side, so choice a) does make a triangle.
I don't know why you are confused. You did the three sums correctly.
Now for each sum, compare it tot eh side you did not add.
Your three sums gave results: 1. 40 m 2. 31 m 3. 37 m Right?
Yes
Now all you need to do is compare each sum to the side that was NOT added. 1. 40 m compared to 14 m 2. 31 m compared to 31 m 3. 37 m compared to 17 m In each case, you see that the sum is greater than the third side right?
I do
yes all greater
Great. That means these three sides CAN make a triangle. That means choice a) makes a triangle is not our answer.
Now we do the same for choice b) We take each two sides at a time and add them. Then we compare the sum with the side we did not add. I'll set it up for you.
so 22
11 plus 11
b)11 m, 11 m, 12 m Let's drop the m (for meters) just to make it quicker to write).
Right. 11 + 11 compared to 12 11 + 11 = 22 > 12
So 22 is greater than 12
Since the sum is greater than the third side, it's good so far. We need to test the other possibilities.
Exactly.
so It's not going to be B correct?
Now we test 11 + 12 = ? and compare with 11
Correct. B is not it. Now we move on to c).
c) 5 m, 7 m, 8 m 5 + 7 = ? compared to 8 7 + 8 = ? compared to 5 5 + 8 = ? compared to 7
Is each sum in b) greater than the third side?
1) 12 and 2) 15 and 3) 13
8 is the same
12 > 8 15 > 5 13 > 7 Each sum is greater than the third side. Once again, c) works.
So now D
c) works meaning it makes a triangle, so it's not our answer.
I hate math because It takes forever to get done with just one problem
Now let's look at d)
21 m, 6m, 10m
d) 21 m, 6 m, 10 m
One way to shorten this type of problem is to look for a set of three sides in which one side is much larger than the other two.
21 is much larger then 6 and 10m
We just found it. Notice that 21 is much larger than 6 or 10. Wow, you're ahead of me.
I think to much with math that's my problem
6 + 10 = 16, and 16 < 21 Set d) will not make a triangle, so we found our answer.
more then I have to
there we go!
thank you! you're patient, I'm terrible at math
We went through a long problem, but don't think it;'s a waste of time. 1) we did it together, and now you understand it. 2) after going through 3 choice that were not it, you got to practice that method a bit. 3) we figured out a quick way to do it: look for a set of sides that has one side much larger than the other two.
This is true, wow you're fantastic
You are very welcome, and thanks. Keep practicing, studying & asking questions. That's how you learn.
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