Question

Write a program to compute an employee’s weekly pay and produce a pay slip showing name, gross pay
(i.e. pay before deductions), deductions, and net pay (i.e., pay after deductions).
The program should first prompt the user for:
a) family (last) name
b) given (first) name
c) hourly rate of pay
d) number of hours worked that week (any hours over 40 are paid at double the normal rate)
e) a letter indicating the employee’s tax category

Answer 1

M4thM1nd

Answer 2

@M4thM1nd

Answer 3

what you have done so far?

Answer 4

public static void main(String[]args)
{
System.out.printIn("What is your last name?");
String lastName = In.getString();
System.out.printIn("What is your first name?");
String fristName = In.getString();
System.out.printIn("What is your hourly rate of pay?");
double hourlyRate = In.getdouble();
System.out.printIn("How many hours did you work this week?");
double hoursWorked = In.getdouble();
}
int hoursWorkedOverForty = 0;
if(weekly_pay_rate > 40) {
weekly_pay_rate = weekly_pay_rate * 40;
hoursWorkedOverForty = weekly_pay_rate - 40; //finds extra hrs worked
weekly_pay_rate = hoursWorked OverForty * (2 * hourlyRate);
//above line will add extra hours at double the normal payrate
}
else { //this else statement will be if you work below or equal to 40 hours
weekly_pay_rate = hoursWorked * hourlyRate;
}
letter = In.getChar();
switch (letter){
case 'A..a': System.out.println("There is no tax deduction.");
break;
case 'B..b': System.out.println("Tax is 10% of gross pay.");
break;
case 'C..c': System.out.println("Tax is 20% of gross pay.");
break;
case 'D..d': System.out.println("Tax is 29% of gross pay.");
break;
case 'E..e': System.out.println("Tax is 35% of gross pay.");
break;
}
System.out.println{("Do want $20 from your payment?";)
int

Answer 5

what is going wrong with teh code?

Answer 6

it won't compile

Answer 7

and I am not sure how to add in more code to do the tax deductions and the 20 dollar charity part

Answer 8

i'll try to run it here

Answer 9

could you please post the code in pastebin .com?

Answer 10

ok I've posted it

Answer 11

you have to use System.out.println()

Answer 12

(PRINTLN not PRINTIN)

Answer 13

Print LN? why is that

Answer 14

oh oops, yeah that was an error

Answer 15

You have to write if l not with i

Answer 16

it*

Answer 17

but I think there may be a problem with the program itself

Answer 18

as well

Answer 19

yes

Answer 20

there is not method such as String ln.getString();

Answer 21

i don't actually remember how to receive a string from the keyboard

Answer 22

no problem, thanks for your help

Answer 23

I think I may need to use if else statements to do the tax deductions as well.

Answer 24

yes! you have to create a conditional flux for this problem

Answer 25

i recomend you to seach for it in the java reference

Answer 26

i personally don't like too much of java

Answer 27

Yeah it can be a lot of work.

Answer 28

if i remember well, the process of making the program receive a string is quite boring

Answer 29

you can easily do these things in C/C++

Answer 30

yeah java is just too much code

Answer 31

yes! can you choose the language for this project our you must use java?

Answer 32

i must use java. :(

Answer 33

hello.

Answer 34

I know quite well how to get input from the keyboard-- either with:
import javax.swing.JOptionPane; or
import java.util.Scanner;
Both can read in strings from the user- scanner can read in from what you type in the console- and JOptionPane can read in from what you type in a window box. Which one do you want to learn?

Answer 35

JOptionPane is more gui, probably cooler than scanner.. but scanner might be easier.

Answer 36

Thanks. I fixed my code but I am still getting 1 error. "cannot be resolved to a variable"
Here is my code:
import java.io.*;
import java.text.*;

public class part
{
static InputStreamReader r = new InputStreamReader(System.in);
static BufferedReader br = new BufferedReader(r);

// Read a String from standard system input
public static String getString()
{
try
{
return br.readLine();
}
catch (Exception e)
{
return "";
}
}

// Read a Number as a String from standard system input
// Return the Number
public static Number getNumber()
{
String numberString = getString();
try
{
numberString = numberString.trim().toUpperCase();
return NumberFormat.getInstance().parse(numberString );
}
catch (Exception e)
{
// If any exception occurs, just return zero
return new Integer(0);
}
}

// Read an int from standard system input
public static int getInt ()
{
return getNumber().intValue();
}

// Read a long from standard system input
public static long getLong ()
{
return getNumber().longValue();
}

// Read a float from standard system input
public static float getFloat ()
{
return getNumber().floatValue();
}

// Read a double from standard system input
public static double getDouble ()
{
return getNumber().doubleValue();
}

// Read a char from standard system input
public static char getChar ()
{
String s = getString();
if (s.length() >= 1)
return s.charAt(0);
else
return '\n';
}
public static void main(String[]args)
{
// Declare Variables
double hoursWorked;
double grossPay;
double hours;
double hourlyPayRate;
hoursworked = 0;

// Get the hours worked and the hourly pay rate
System.out.print("How many hours did you work? ");
System.out.print("How much do you get paid per hour? ");


// Calculate gross pay
if (hoursWorked <= 40)
{
grossPay = hoursWorked * hourlyPayRate;
}
else
{
grossPay = (hoursWorked) * (1.5 * hourlyPayRate);
}

// Display the results
System.out.println("You earned $" + grossPay);
}
}

Answer 37

It is saying that hoursWorked cannot be resolved to a variable.

Answer 38

java is a case sensitive language, you left the w lower-case when you did hoursworked = 0 -- it's declared as double hoursWorked; small thing

Answer 39

Thanks again!

Answer 40

ya np. You probably have other errors because you didn't initialize the variables up top.. if it still doesn't work try this:

double hoursWorked = 0;
double grossPay = 0;
double hours = 0;
double hourlyPayRate = 0;
hoursWorked = 0;

Answer 41

it's a finicky thing-- the compiler is awfully sensitive lol.

Answer 42

yeah, one more thing, when doing the switch statements, the program needs to be able to respond to either a case of upper case A AND lower case a, so would it work if I went:
case 'A..a' for each case?

Answer 43

I'd guess not.. but I have a way to get around that obstacle.
if you want to do a switch statement which operates a case when the value is multiple things-- I do this:

char chap = 'a';
switch(chap) {
case 'B':
I'm a statement;
break;
case 'A':
case 'a':
I'm a statement;
break;
default:
I'm a statement; //default executes if none of the other cases are true
break;
}

if chap = 'B' the switch statement will execute case B then skip the rest of the statement. if chap = a, or chap = A, it will execute the statements under case A & case a: this can be done in different ways too-

Answer 44

Here is a program that is self-explanatory in working syntax:

int aNumberBetween1and10 = 6;

switch(aNumberBetween1and10) {
case 1:
case 2:
case 3:
case 4:
case 5:
System.out.println("I am a number between 1 and 5.");
break;
case 6:
case 7:
case 8:
case 9:
System.out.println("I am a number between 6 and 9.");
break;
case 10:
System.out.println("I'm 10.");
break;
default:
System.out.println("I am not a number between 1 and 10.");
break;
}

Answer 45

That makes great sense thanks :)

Answer 46

np, let me know if you need help with keyboard input.

Answer 47

though if you have certain statements execute in a large range- if-else-if statements are better than switch.

Answer 48

Just another question, I am trying to make it so that my program asks the user for a bunch of info and then returns it all at the end, how would I write the return values, would I be doing them after the print statements?

Answer 49

yea, say I have 3 string variables that the user entered,
String str1, str2, str3;
Let's say the user inputs as follows:
str1 = "James Donson";
str2 = "42 years old";
str3 = "I like Taco Bell";
Now if I want to print them, I put them inside a print or println method.
System.out.println("Name: " + str1 + ".");
System.out.println("Age: " + str2 + ".");
System.out.println("Favorite Restaurant: " + str3 + ".");

This will output the following::::

Name: James Donson.
Age: 42 years old.
Favorite Restaurant: I like Taco Bell.

Alternatively, I'll show you what happens if you do the print instead of println method::

System.out.print("Name: " + str1 + ".");
System.out.print("Age: " + str2 + ".");
System.out.print("Favorite Restaurant: " + str3 + ".");

This will print:
Name: James Donson.Age: 42 years old.Favorite Restaurant: I like Taco Bell.

println will output a line, then automatically move to the next one, while print will continue on the same line.

Wherever I had string variables, you can exchange them with int values ect.