x-intercept of (2x+7)(x-1)
Find out where the numerator is equal to zero
Assuming that you mean y = (2x+7)(x-1), set y to 0 and determine which values of x give that value.
For example, the x-intercepts of the equation y = (x+a)(x-b) would be -a and b.
hmm. I've tried to put in -7, 1 and 7, -1 and 7,1
I'm really confused with this problem. Its really long and doesn't tell me if anything is wrong or right along the way. can i attach and you look?
Since it's (2x+7), not (x+7), the x-intercept will not be -7.
Think of it this way- if 2x + 7 = 0, what is the value of x?
7?
7/2?
Not exactly, but close. Solve it like you would any other equation: \[2x+7 = 0\]\[2x = -7\]\[x = \frac{ -7 }{ 2 }\]
Then, you do the same with the other part of the factored equation- what is x in x - 1=0?
1
So you have your x-intercepts then :)
can you look at the attachment? it says the problem is wrong still. idk what is wrong though
You're telling them that the intercepts are 7 and -1, not -7/2 and 1
yea, i changed that part but it says its still wrong
Maybe you have to put it in the form (x, 0)
Or try putting it in decimal form.
wont allow decimals.
i have no idea
well that part of the problem is right because the percentage i have went up
but something else is wrong and idk what
Looks all right to me. Must be the applet acting up.
No wait.
Maybe you're suppsoed to put the domain as [-inf, inf]?
i dont think so. in the example it says to put it in as (-inf, inf)
Well, either something's slightly off about the way you're imputting your answers, or the applet's messed up, because the answers are right.
it might be the site because theres another problem that i'm almost positive is right
this one
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