Question

what mass of NH3 can be produced from 2 mol of H2 reacting with excess N2 in the reaction?

Answer 1

N2+H2-> NH3
N2+3H2->2NH3
^ ^23.8g
62.7g
no. of moles = mass/molar mass
calculate no of moles of N2 and H2
then by conservation,
we can get the no of moles of NH3 products
then by no. of moles = mass/molar mass, we can get mass of product

Answer 2

what is the mass?