Please could I get some help with this last question I have been waiting for 2 hours please! I just need it in (P/X)/DP/DX form please! Demand function 128 ------ +2 x^2 Quality demand x = 4 Find the price elasticity of demand for the demand function at the indicated x-value.
@JackleBee
you mean you want to get rid of the fraction?
yes
shoot, did you try logs?
nope, not sure what that is.
y doesn't equal to anything at the moment right?
right
Ive tried different methods, but not getting a clear answer
which methods did you try? you might have missed a step
I tried 2x= 128+ 2 to get rid of the fraction, but I got the wrong answer
lol why 2x?
I just tried to move the x^2 over to one side then solve 128/2 to get 64
128 ------ +2 = y x^2 did you try square root?
like move it, and then square root?
man, i'm stumped on this one, I'll get this other guy who might help. ;p @satellite73
sorry dude, but I want to see how this is solved as well xD
same here. I know the process, but the fraction is throwing me off
@satellite73 you think you can help us sir? and yeah, that fraction xD
I think I remember @satellite73
I'm trying to get this problem into (P/X)/DP/DX form, but the fraction is throwing me off
What is P when x = 4 ?
10?
err 10
so you'll have P/x = 10/4 = 2.5
dP/dx is simply the derivative of P with respect to x
think of it as P = 128x^(-2) + 2 and use the power rule
\[\frac{ -256 }{ x^3 }\]
good
now I think you plug in x = 4 into dP/dx
I get -4
I got 2.5/-4 = -5/8
so, (P/x)/(dP/dx) = (2.5)/(-4) = -0.625 essentially the price elasticity of demand is -62.5% for every increase of the price, the demand drops by 62.5%. I think this is only true near the value x = 4
Wow thank you so much ! :) I have been stuck in that problem for the longest.
np
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