Question

PLEASE HELP IDK WHAT TO DO
Problem attached
if anyone could even help me start it I'd appreciate it so much

Answer 1

a screen shot will work better than copying and pasting in to a word document
doesn't really work

Answer 2

how do i do a screenshot? thats what i put in the word doc

Answer 3

this is the problem

Answer 4

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. 532 feet of fencing is used. Find the dimensions of the playground that maximize the total enclosed area. Remember to reduce any fractions and simplify your answers as much as possible.

Answer 5

use "print screen" and attach
that would help probably has a picture along with it

Answer 6

it doesn't have a picture.

Answer 7

print screen doesn't do anything

Answer 8

area is \(xy=532\)
amount of fence used is \(3x+2y\)

Answer 9

i take it this is a calculus problem right?

Answer 10

i'm not sure what to do after that

Answer 11

well im in MTH 103. so its supposed to be a college algebra class.

Answer 12

since \(xy=532\) you have \(y=\frac{532}{x}\) then the fencing used is
\[f(x)=3x+\frac{2\times 532}{x}\] minimize that one

Answer 13

you cannot do this with algebra

Answer 14

yea. i'm convinced they're setting us up to fail because calc has come into homework multiple times with no explanations or examples

Answer 15

oh damn hold the phone i read it wrong

Answer 16

the amount of fencing is \(532\) not the area !!

Answer 17

lets start again, this time
\[3x+2y=532\]

Answer 18

that means \[2y=532-3x\] or
\[y=266-\frac{3}{2}x\]

Answer 19

then
\[A=xy\] substituting gives
\[A(x)=x(266-\frac{3}{2}x)=266x-\frac{3}{2}x^2\]

Answer 20

find the maximum by finding the vertex

Answer 21

how do i find the vertex?

Answer 22

the first coordinate of the vertex of
\[y=ax^2+bx+c\] is \(-\frac{b}{2a}\)

Answer 23

in your case it will be
\[-\frac{266}{-\frac{3}{2}}=\frac{2\times 266}{3}\]

Answer 24

532/3

Answer 25

ok yes

Answer 26

the second coordinate is what you get when you replace x by that number

Answer 27

in the y=ax^2 etc equation?

Answer 28

yeah lets cheat

Answer 29

cheat?

Answer 30

http://www.wolframalpha.com/input/?i=266x-3x^2%2F2

Answer 31

scroll down to where is says "global max"

Answer 32

max{266 x-(3 x^2)/2} = 35378/3 at x = 266/3

Answer 33

hmm, those are the sides?

Answer 34

webworks says its wrong