Find a ⋅ b. a = <2, 4>, b = <2, 5>
these are the answer choices <4, 9> 24 <4, 20> 16
and your choice is?
well I thought it was <4,20> but that clearly isn't an answer choice
hmm, a dotproduct produces a number, not a vector
stack, multiply, add the resutls
a = <2, 4> b = <2, 5> 4 + 20
so would it be 24?
i organize them like this to avoid misplacing the information all i have to do then is multiply down the columns and add the resutls
yes, 24
ah ok I see how you do this...
:) practice makes perfect ... and then dementia sets in lol
haha :) would you mind helping me with a few more?
one more, need to start heading to bed
Find the angle between the given vectors to the nearest tenth of a degree. u = <2, -4>, v = <3, -8>
this involves the definition of a dotproduct \[|u||v|cos(a)=u\cdot v\]
so we can start with dotting u to v, what do we get?
what is a?
a is alpha, or angle .... its what we will end up solving for also notice that when we dot a vector to itself: (x , y) (x , y) ---------- x^2 + y^2 the results are almost the length .... sqrt(x^2 + y^2) defines the length of a vector
I don't really understand...
do the dotproducts: u.v u.u v.v we will use these in the "formula" in order to solve for the required angle
what am I multiplying? Idk at all
the first think you posted asked you to find the dot product of 2 vectors, i demonstarted what to do .... you said you "ah ok I see how you do this..." now given: u = <2, -4> and v = <3, -8> find u dot v and u dot u and v dot v
ao you basically do them separately and then add them together at the end?
do them seperately, and then we will use them as needed. at the moment we simply need to know what they are.
ok so u.v is 38 uu is 20 and vv is 73?
let me chk :) u = <2, -4> v = <3, -8> 6 + 42 = 40 u = <2, -4> and v = <3, -8> u = <2, -4> and v = <3, -8> 4+16 = 20 9 + 64 = 73 correct
how do I solve for the angle then?
now we can work the problem\[|u||v|cos(a)=u\cdot v\] \[|a|=\sqrt{a\cdot a}\] sooo \[\sqrt{20}~\sqrt{73}~cos(a)=40\] divide off the sqrts and inverse the cosine to detemrine a \[cos(a)=\frac{40}{\sqrt{20}~\sqrt{73}}\] \[a=cos^{-1}\left(\frac{40}{\sqrt{20}~\sqrt{73}}\right)\]
ok well I tried plugging it into my calculator but it keeps saying error
thats cause the result is bigger than 1 ....
what would that mean?
3.0° 6.0° -7.0° 16.0° these are the answer choices
u = <2, -4> v = <3, -8> 6 + 32 = 38 you had the right number, i messed it up ... said it was 40
\[a=cos^{-1}\left(\frac{38}{\sqrt{20}~\sqrt{73}}\right)\] much better
so 6 degrees?
yep
all that work defining the dots, and i used 40 instead of 38 :) i mentioned the dementia part right?
thank you so much for your help:) and yes I remember you mentioning dementia:p lol well have a good night you should probably go to bed:)
thnx, and good luck ;)
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