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Chemistry 19 Online
OpenStudy (anonymous):

How to find the solubility of Li3PO4 at 25 degrees C given Ksp 2.37x10^-4?

OpenStudy (preetha):

Write the equation for the dissociation. Li3PO4(s) <--> ?

OpenStudy (preetha):

Then write the equation for Ksp = [ ] [ ]/[ ] ? for this compound.

OpenStudy (preetha):

Assume the solubility of Lithium phosphate is x moles/L. That means when you put solid Lithium Phosphate into water - you get x moles of Phosphate ions in solution and a proportionate amount of Lithium ions (You have to write the equation first). Your job is to calculate x knowing the balanced equation.

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