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evaluate limit as x approaches zero from the right. (tan 8x)^x.
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\[[\tan(8x)]^x=e^{\ln([\tan(8x)]^x)} \]
hmmmm
i would go right to the definition \[\large[\tan(8x)]^x=e^{x\ln([\tan(8x)])}\]
but what's the answer?
I think we need L'Hospitals Rule
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\[e^{\lim_{x \rightarrow 0^+}x \ln(\tan(8x))}=e^{\lim_{x \rightarrow 0^+}\frac{\ln(\tan(8x))}{\frac{1}{x}}}\]
The answer was 1
very good
why didn't you tell me that first??
You have to do the work to determine the answer.
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