Please help integrals
\[\int\limits (1-x+2x^2-x^3)/(x(x^2+1)^2)\]
dx at the end
I know i'm supposed to partial fraction decomposition but I get stuck while doing that.
I know i'm supposed to *use*partial fraction decomposition but I get stuck while doing that.
Show me your steps or where you get stuck. I'll help you along the way.
Alright thanks, give me sec to type
\[-x^3+2x^2-x+1=A(x^2+1)^2+Bx(x^2+1)+Cx\] \[=Ax^4+A2x^2+A+Bx^3+Bx+CX\] then... -x^3=Bx^3 2x^2=A2x^2 -x=Bx+Cx A=1 so my question is what would i make the Ax^4 equal to...0?
You left....
so any ideas? Do you understand my question, sometimes I can be difficult to understand.
Sorry something came up, but you have done it wrong in that you've skipped some steps in getting to this formula. I have to go, sorry. But this should help at least http://www.wolframalpha.com/input/?i=partial+fractions+%281-x%2B2x%5E2-x%5E3%29%2F%28x%28x%5E2%2B1%29%5E2%29
alright thanks
I think you should be starting with \[ \frac{A}{x} + \frac{Bx+C}{x^2+1} + \frac{Dx+E}{(x^2+1)^2} \]
hhmm. I set it up a different way, but obviously i'm wrong. I'll trying redoin it your way, and see if Rabya! has anything to add.
thanks phi
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