Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (happykiddo):

Please help integrals

OpenStudy (happykiddo):

\[\int\limits (1-x+2x^2-x^3)/(x(x^2+1)^2)\]

OpenStudy (happykiddo):

dx at the end

OpenStudy (happykiddo):

I know i'm supposed to partial fraction decomposition but I get stuck while doing that.

OpenStudy (happykiddo):

I know i'm supposed to *use*partial fraction decomposition but I get stuck while doing that.

OpenStudy (kainui):

Show me your steps or where you get stuck. I'll help you along the way.

OpenStudy (happykiddo):

Alright thanks, give me sec to type

OpenStudy (happykiddo):

\[-x^3+2x^2-x+1=A(x^2+1)^2+Bx(x^2+1)+Cx\] \[=Ax^4+A2x^2+A+Bx^3+Bx+CX\] then... -x^3=Bx^3 2x^2=A2x^2 -x=Bx+Cx A=1 so my question is what would i make the Ax^4 equal to...0?

OpenStudy (happykiddo):

You left....

OpenStudy (happykiddo):

so any ideas? Do you understand my question, sometimes I can be difficult to understand.

OpenStudy (kainui):

Sorry something came up, but you have done it wrong in that you've skipped some steps in getting to this formula. I have to go, sorry. But this should help at least http://www.wolframalpha.com/input/?i=partial+fractions+%281-x%2B2x%5E2-x%5E3%29%2F%28x%28x%5E2%2B1%29%5E2%29

OpenStudy (happykiddo):

alright thanks

OpenStudy (phi):

I think you should be starting with \[ \frac{A}{x} + \frac{Bx+C}{x^2+1} + \frac{Dx+E}{(x^2+1)^2} \]

OpenStudy (happykiddo):

hhmm. I set it up a different way, but obviously i'm wrong. I'll trying redoin it your way, and see if Rabya! has anything to add.

OpenStudy (happykiddo):

thanks phi

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!