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If you have a function with slope m, then why doesn't the inverse function have a slope of -1/m?
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:O haha brb :P
inverse is defined as reflection about y=x line, so how the it related to perpendicular stuff -1/m ?
Ok ok this was just a lame trick question I was thinking about because I know some people mess up the slope of an inverse function with a perpendicular line and wanted to see who I could fool. here's a calculus way of deriving it though for inverse functions having inverse slopes. \[\LARGE y(x(y))=y \\ \LARGE y'(x(y))x'(y)=1 \\ \LARGE y'(x(y))=\frac{1}{x'(y)}\]
you can get negative reciprocal slopes for constant functions parallel to axes i think
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