Question

What is the distance from (−3, 1) to (−1, 5)? Round your answer to the nearest hundredth.

Answer 1

Formula for the distance between two points:

\(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

\(x_2 = -1\)
\(x_1 = -3\)

\(y_2 = 5\)
\(y_1 = 1\)

Answer 2

Can you plug them in and solve? @Bballplayer48

Answer 3

Have you considered the Distance Formula? iGreen did.

Answer 4

No I don't know it

Answer 5

1) 7.9
2) x = 7
3) y = 4

Answer 6

@iGreen Do I find the square root?
at the end

Answer 7

Well, there you go, then. Use the substitution indicated by iGreen and you'll be done in no time.

Answer 8

Ok ty

Answer 9

1/
Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:
sqrt ( (x2-x1)² + ( y2-y1) )
2 and 3/
the Midpoint Formula is :
( (x1+x2)/2, (y1+y2)/2 )

Answer 10

there you go

Answer 11

problem solved

Answer 12

@Bballplayer48

Yes, you do..

Answer 13

Tell me what you get. @Bballplayer48

Answer 14

I got 2.449? @iGreen

Answer 15

I don't think that's correct.

Answer 16

Can you tell me how you got it?

Answer 17

It isn't

Answer 18

3.60?

Answer 19

\(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

\(\sqrt{((-3)-(-1))^2 + (5-1)^2}\)

Subtract -3 - -1, what do you get?

Answer 20

OHHHH I forgot to put the exponent up top

Answer 21

One sec

Answer 22

@iGreen I got 8

Answer 23

But thats wrong to :(

Answer 24

Forget it :(

Answer 25

-3 - -1 = -2

(-2)^2 = 4

5 - 1 = 4

4^2 = 16

16 + 4 = 20

sqrt of 20 = 4.47

Answer 26

@Bballplayer48