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Mathematics 8 Online
OpenStudy (anonymous):

Which equations represent the line shown in the graph? Choose all answers that are correct.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@shortycme

OpenStudy (anonymous):

please anyone

OpenStudy (akashdeepdeb):

Do you know how to find the equation of a line? You are given two points. You may find the slope by using rise upon run and then find the equation of the line here!

OpenStudy (anonymous):

no should i if its the lastquestion i just ned the answer and yes i have to pick more than one

OpenStudy (anonymous):

@iGreen

OpenStudy (akashdeepdeb):

You need to find the equation of the line using the 2 points. I do not know the answer.

OpenStudy (anonymous):

no please help me

OpenStudy (anonymous):

@sleepyjess

OpenStudy (akashdeepdeb):

Okay, sure! :D Do you know what slope is? Or how to find it?

OpenStudy (anonymous):

mayb this is my first quiz on it D:

OpenStudy (anonymous):

shorty you know?

OpenStudy (anonymous):

/) /) ( ^_^) C (") (")

OpenStudy (akashdeepdeb):

If you have 2 points: (x1,y1) and (x2,y2) Then the slope of the line is: \[m = \frac{y_2-y_1}{x_2-x_1}\]

OpenStudy (anonymous):

is that supposed to help?

OpenStudy (anonymous):

just give me the answer please ;,(

OpenStudy (akashdeepdeb):

This is the line equation: \((y-y_1) = m(x-x_1)\) You can calculate m from the formula I gave above. (x1,y1) is one of the points. y and x are the variables. Find the equation. If I gave you the answer directly I'd be breaking the OpenStudy Code-Of-Conduct rules.

OpenStudy (anonymous):

o just realized your ambassador O_O

OpenStudy (anonymous):

then do so

OpenStudy (anonymous):

i need help on my last question

OpenStudy (anonymous):

more like i need the answer

OpenStudy (anonymous):

@Caus

OpenStudy (anonymous):

@robtobey

OpenStudy (anonymous):

@shortycme

OpenStudy (anonymous):

@CausticSyndicalist

OpenStudy (anonymous):

idk im sorry

OpenStudy (anonymous):

its ok

OpenStudy (anonymous):

@kropot72

OpenStudy (anonymous):

@c0decracker

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