Please help!!!! What point in the feasible region maximizes the objective function?
objective function: C=5x-4y
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@campbell_st could you help me with another? :)
What point in the feasible region maximizes the objective function constraints: x>=0 y>=0 -x+3>=y y<=1/3 x+1 Objective function: C=5x-4y 1. Region limited by : x>=0 y>=0 x + y <= 3 is the interior of rectangle triangle of summits (0,0), (0,3)and (3,0) if we add the constraint y <= 1/3 x + 1 it's the part in the triangle below this line : the summits are (0,0) , (0,1) , (3,0) and the intersection point of line L of equation : y = x/3 + 1 and the hypotenuse of the triangle (equation x+y = 3) let's solve this : 3 - x = x/3 + 1 4x/3 = 2 x = 3/2 and y = 3/2 now the Criteria : C = 5x - 4y are lines parallel to line of equation 5x - 4y = 0 or y = (5/4)x so C is maximum at an edge of the domain : points are O ( 0 ,0) A( 3 , 0) B ( 0 ; 1) D ( 3/2 ; 3/2) criteria is C = 5x - 4y C (A) = 5*3 - 4*0 = 15 C(B) = 5*0 - 4*1 C(D) = 5* (3/2) - 4*(3/2) = 3/2 so C is max at point A(3 ; 0) <==== answer
Thank you for your time :D
wow. Thanks @here to help.
No problem
Could you help with another? @Here_to_Help15
yes
sorry i took long was busy
I started a new q i will tag you in it
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