@amistre64 If you are dealing from a standard deck of 52 cards, how many different 5-card hands could have at least two face cards (jacks, queens, or kings?
that did not help me at all lol
At the bottom :p
nvm i got how to do it thanks anyways
Sorry ;-;
i wonder assume we use jacks 4C2 face cards, (52-4)C3 remaining options remove the jacks to avoid counting them again assume queens 4C2 face cards, (52-8)C3 remaining options remove the queens to avoid counting them again assume kings 4C2 face cards, (52-12)C3 remaining options
wonder if and where the logic in my thoughts fail
theres a flaw in it ... im sure
I did the indirect way. So with no restrictions 52C5 What you dont want it is no face card or just 1 face card 52C5-(12C0*40C5)<--No face + (12C1*40C4)<--1 Face card)=844272
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