Use power series to solve (1+x^2)y''+xy'+(3x+2)y=0
Well, are you expecting someone else to drag through that for you? Let's see where you started, at least.
well maybe he/she dont know the steps :O
@keynote start by dividing term on leading coefficient
I got into the substitution and am stuck there
oh then type what u got so far
See, this is what I am talking about. Let's see your work so a wonderful, kind, and giving volunteer doesn't have to do it for you. Very good.
\[\sum_{n=2}^{\infty} n(n-1)a_nx^{n-2}+\sum_{n=2}^{\infty} n(n-1)a_nx^{n}+\sum_{n=1}^{\infty} na_nx^{n}+\sum_{n=0}^{\infty} 3a_nx^{n+1}+\sum_{n=0}^{\infty} 2a_nx^{n}+\]
That's what i have so far
That's excellent. Now, you just have to change your indeces so they match up. You can't have one start at 0, one at 1 and the other at 2. Mind you, I can't really tell if that is right, since it is cut off by the screen. It does appear to me that you have the right idea.
So how do i change the indeces. Thats where my problem is
Very carefully... \(\sum\limits_{n=1}^{\infty}na_{n}x^{n} = \sum\limits_{n=0}^{\infty}(n+1)a_{n+1}x^{n+1}\) That's about it.
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