Question

@tkhunny
The social convenor has
12 volunteers to work at a school dance.
Each dance requires 2 volunteers at the
door, 4 volunteers on the floor, and
6 floaters. Joe and Jim have not volunteered
before, so the social convenor does not want
to assign them to work together. In how
many ways can the volunteers be assigned?
please check my answer

Answer 1

Indirect method
without any restriction: 12C2*10C4*6C6=13860
Combinations with both of them working together
at the Door: 1*10C4*6C6=210
At the Floor: 10C2*8C2*6C6=1260
As Floaters: 10c2*8C2*4C4=3150
=210+1260+3150=4620
No restriction - What you Dont Want= 13860-4620=9240

Answer 2

Does my answer make sense, or have i missed something?

Answer 3

@tkhunny any idea yet?

Answer 4

I tend to be horrible at counting, but the ONLY thing I find wrong with your presentation is the 8C2 in the "Floater" section. s/b 8C4 It's just a typo, since you have the right total.

Answer 5

oh my bad yes its a typo, thanks :)