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Mathematics 13 Online
OpenStudy (anonymous):

Did I do this right?

OpenStudy (anonymous):

OpenStudy (anonymous):

How do I do question e and d?

OpenStudy (anonymous):

for the first want, i just want to know if i did one question right. and the second, the questions e and d were indeed challenging! xD

OpenStudy (anonymous):

anyone help is awesome!

OpenStudy (anonymous):

#1 how did you get (sqrtx+7) = to (sqrt 5 +7)?

OpenStudy (anonymous):

f(x) is x+2 and p(x) is radical 5+7, so since its addition, i added them.

OpenStudy (anonymous):

did i do it wrong?

OpenStudy (anonymous):

I'm not sure actually. Sorry I can't be any help.

OpenStudy (anonymous):

ok ):

OpenStudy (anonymous):

The answer of e = k(g(x) It looks like you got one of the answers for d. The second would just be the reverse. So you would have j(g(x)

OpenStudy (anonymous):

K (g (x)) doesnt work for e cause u need an x on the numerator

OpenStudy (anonymous):

\[k(g(x))= \frac{ 1 }{ \frac{ 1 }{ x }+1 }\]\[\frac{ 1 }{ \frac{ 1 }{ x }+\frac{ x }{ x} }\]\[\frac{ 1 }{ \frac{ x+1 }{ x} }\]\[1*\frac{ x }{ x+1 }\]\[\frac{ x }{ x+1 }\]

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