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Mathematics 17 Online
OpenStudy (anonymous):

Hey, is there anyone that can help me with Stats?

OpenStudy (anonymous):

The problem im having is that I don't know how to start this. All that's given to me is a table, a Pop mean of 222, N = 11, Alpha = .01. How would i start doing problem?

OpenStudy (amistre64):

it depends on what it is you are looking for ...

OpenStudy (anonymous):

Oh! sorry, i'm looking for a difference between the levels my group (the table im given) and the pop mean

OpenStudy (amistre64):

so the difference between some table value x and the mean is: x-mean?

OpenStudy (amistre64):

if you can post a picture of the problem to avoid any errors in transmission, that would be helpful

OpenStudy (anonymous):

Will do, one second

OpenStudy (anonymous):

OpenStudy (amistre64):

so its pretty much a hypothesis test to determine if theres a difference or not between the means

OpenStudy (amistre64):

Ho: mu1 - mu2 = 0 Ha: mu1 - m2 not= 0

OpenStudy (anonymous):

i know this might sound like a stupid question but just for clarification, when doing a T test, i should always declare it in that format, right? mu1 - mu2 = 0 means the same as "mu1=mu2"

OpenStudy (amistre64):

correct

OpenStudy (amistre64):

how you define it should match your material :) but both ways are equivalent statements

OpenStudy (anonymous):

Another quick question, df = 11 + 11 + 2. I figured the second N (of the population) to be 11 also, right?

OpenStudy (amistre64):

dF eh ... does your material give you the simpler version or the more complicated version?

OpenStudy (anonymous):

Simple I presume. df = n1 + n2 + 2

OpenStudy (anonymous):

I put 11 because the total number for the problem are 11, I just don't know how to go about getting the second n.

OpenStudy (amistre64):

we dont have 2 sample means do we?

OpenStudy (amistre64):

and its -2 of we were comparing the means between 2 samples ...

OpenStudy (anonymous):

Brb, one second, need to look over my notes, just realized that I'm totally looking at the wrong test for the information that I am given

OpenStudy (amistre64):

im thinking since this isnt a pooled thing .... \[t=\frac{\mu_1-\mu_2}{\sigma/\sqrt n}\]

OpenStudy (anonymous):

Yep, that's the one i just found. wow i feel stupid. I don't know i was so set on using a test that compares things when im only given one piece of information

OpenStudy (anonymous):

Would you mind checking my work once i'm done to make sure I did it right?

OpenStudy (amistre64):

sure, i need the practice :)

OpenStudy (amistre64):

by the way, do we have a table to work with or a stats calc like a ti83?

OpenStudy (anonymous):

Ah, a table. I can send you a picture of that too. I hit a slight bump, can you set me straight? the formula you gave above has a Mu1 and Mu2, the formula given to us in lecture is \[t = \frac{ X - \mu }{ s /\sqrt{n} }\] *X-Bar* no X. What in the equation is what?

OpenStudy (amistre64):

X = sample mean, u = pop mean

OpenStudy (amistre64):

s is the sample standard deviation and n is the sample size

OpenStudy (anonymous):

Given the table, I took the average of the cholesterol = 209.90. This is the X-bar correct?

OpenStudy (amistre64):

yes, 209.91 is what im using

OpenStudy (anonymous):

What are you using for s?

OpenStudy (amistre64):

havent you calculated it yet?

OpenStudy (anonymous):

So, -12.9/10.03 = -1.24. which falls within the crit value = reject

OpenStudy (amistre64):

\[\sum(x-\mu)^2\] \[\sum(x^2-2x\mu+\mu^2)\] \[\sum x^2-2\mu~\underbrace{\sum x}_{=\mu}+\sum\mu^2\] \[\sum x^2-2\mu^2+\sum\mu^2\] \[\sum x^2-\mu^2\] just in case you didnt have a shortcut formula ...

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=%28209.91-222%29%2F%2833.294%2Fsqrt%2811%29%29 out t stat is going to be about: -1.2044

OpenStudy (amistre64):

this doesnt tell us much in the way of a solution yet. its just what we use to determine a p-value to compare with. unless you know of the t stat to compare with

OpenStudy (amistre64):

|dw:1413858569022:dw|

OpenStudy (amistre64):

unless you know what the t boundaries are for in the distribution setup, we need to take this futher

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