Question

Find a polynomial equation with integer coefficients that has the given numbers as solutions and the indicated degree. 1, 2+3i; degree 3

Answer 1

solution means root of the equation

Answer 2

one root =1
now complex root always occur in pair

Answer 3

so the other root will be 2-3i

Answer 4

u have 3 root now

Answer 5

=(x-x1)(x-x2)(x-x3)
it ie the equation with root= x1,x2,x3

Answer 6

ok will it look like this?
(x-1) (x-2+3i) (x-2-3i)

Answer 7

yep u did that ...well done :)

Answer 8

ok thank you.

Answer 9

welcome:)

Answer 10

how would you foil this?

Answer 11

@gorv

Answer 12

yeah say???

Answer 13

where u need help??

Answer 14

foiling this (x-1) (x-2+3i) (x-2-3i)

Answer 15

http://www.wyzant.com/resources/lessons/math/algebra/foil

Answer 16

thanks. I know how to use it but im not sure how the equation turns out with imaginary numbers?

Answer 17

just follow that consider complex number as aor something and proceed

Answer 18

and in the end replace a by complex number

Answer 19

ok

Answer 20

is this right x^3-5x^2+17x-13 ? @gorv

Answer 21

@dan815 can you help?

Answer 22

yea