For which operations is the set {–1, 1} closed? Choose all answers that are correct. A. addition B. subtraction C. multiplication D. division
Didn't get the question properly.. :(
:/ I'm not really sure what the logic is to solve this, I have 4 more questions.. ;-;
Why does it put ��������� in the brackets? O_o
What?
Okay..
Nevermind.. I'm guessing it's C and D because, (-1) + 1 = 0, but 0 isn't in the brackets.. And same goes for subtraction since it'll end up with -2. While Multiplication & Division have -1/1 as the product/quotient..
Multiplication is okay.. :)
Division is also looking good to me.. :)
I'll see if I get it correct then reply when I'm done with the other 4 questions. =D
What are other 4?
Which equations show that the set of whole numbers is closed under multiplication? Choose all answers that are correct. A. –1 • –1 = 1 B. 0 • –1 = 0 C. 0 • 2 = 0 D. 2 • 1 = 2 This is the second question.
Whole numbers are : 0, 1, 2, ..................
Negative numbers don't count, correct?
Negative numbers are not allowed.. So, you are left with two options..
C And D?
Good.. :)
Which sets of numbers are closed under addition? Choose all answers that are correct. A. {0, 2, 5, 8} B. even integers C. rational numbers D. {0}
That's the third question..
D is for sure answer :P
A?
8 + 5 = In the set or not?
Oh right.... :/
Even integer set, when you add two even you are going to get another even.. :)
\(2 + 4 = 6\), \(6\) is also even.. :)
Ohk..
Are rational numbers like a/b and can't end up with 0?
Even Integer Set is : \(\{..... -4, -2, 0, 2, 4, 6...........\}\)
I did not get you.. :(
Hold on, lemme google rational numbers. :3 Kinda forgot what it was.
a/b where a and be are integers and b is not zero
Rational numbers contain whole number + integers.. Decimals also allowed, terminating and recurring too..
So is 4.5 rational? because it is 9/2 I think..?
yep.
See, 4.5, the decimal ends at 5, terminating one, it is rational..
Ok
So then C. Rational Numbers wouldn't be the answer?
the sum of two rational numbers is a rational number
He he he, I was about to ask Zarkon for confirmation.. :)
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]
If addition of two numbers is giving you a rational number which will be in the set, then it is your answer.. :)
Ok
three answers in this.. Now what is number 4 ??
Numbers p and q are whole numbers. Which statements are always true? Choose all answers that are correct. A. p + q is a whole number B. p – q is a whole number C. p • q is a whole number D. is a whole number
I'm thinking that it's A, B, C
Since we don't know what P and Q is, it might be 6 divided by 4 or something..
Plus I don't think that a sum would end up with a decimal when there is 2 whole numbers.. And same goes with subtraction.
they are whole numbers.. :P
\(2 - 5 = \) whole number or not?
Yes, but a whole number can still contain a decimal for the quotient..
Ahh wasn't thinking about that.. :P
Addition is perfect..
And so is multiplication?
yep, good..
Should we head onto question 5?
Division and subtraction can be killed here.. :)
Ohk.
Any doubt anywhere?
Nope.
For first one, division and multiplication hold good.. :)
Yep.
Okay, good, you interacted well, I appreciate you for that.. :)
Question 5? :P
Still?
We only did up to question 4. :P
Or you have 4 without counting first one?
Okay, let it come.. :P
Is the set of multiples of 6 closed under subtraction? Explain why or provide a counterexample if not. A. Yes, because the difference of any two multiples of 6 is equal to 6. B. Yes, because the difference of any two multiples of 6 is also a multiple of 6. C. No, and a counterexample is 6 – 6 = 0. D. No, and a counterexample is 6 – 18 = –12.
What about b?
\(0\) is also a multiple of \(6\)..
'cause of 2 x 3 = 6..
wait..
I thought 6 x 0 = 0?
What do you think? What this set is?? Can you write this set?
Write this set? write the set for multiples of \(6\).. :)
Okay.\[6 \times 1\]?
It has to be all multiplication right?
You are given a set, do you know what that set is?
the set they gave me was multiples of 6.. Or 2 6's..
The set so called "Multiples of \(6\)" is the set: \[\{..........-18, -12, -6, 0, 6, 12, 18..........\}\]
Multiples of \(6\) means number which are divisible by \(6\), giving \(0\) as remainder.. :)
getting?
A little bit
2, 3 are factors of 6 but not the multiples of 6.. :)
do you know the table for 6??
I do
the numbers in the table are nothing but multiples of 6..
Yes.
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