Can someone check my work please? a 1.5kg ball is attached to a vertically hung spring with spring constant K. it stretches .23m. this system is brought to SHM. Find the frequency in hertz.

Question

Can someone check my work please?  a 1.5kg ball is attached to a vertically hung spring with spring constant K. it stretches .23m. this system is brought to SHM. Find the frequency in hertz.

adamconner · Answer

i know that Frequency= sqrt(K/m) right?
so I found K using F=Kx
since its vertical so its  mg=Kx
so..
(1.5)(9.8)=K(.23)
K=63.9 N/m ....??

adamconner · Answer

so $$f=\sqrt{\frac{ 63.9 }{ 1.5 }}$$   

Frequency= 6.5Hz

adamconner · Answer

right?

anonymous · Answer

Almost.
You have the spring constant correct, but you have then calculated the angular frequency, which is 2pi times f.
You need to divide by 2pi to get the frequency in Hz.

adamconner · Answer

ooh right.. so f= 1/(2pi) sqrt (63.9/1.5)
so i get f=1.03Hz ?

anonymous · Answer

i think that is right