Can someone please help me solve this problem? It's about inequalities in algebra. I know how to do these it's just this one is a bit confusing for me.
Here is the problem: \[q + 12 - 2(q - 22) > 0\]
\[q >55\]
Okay. But how did you get that?
I would like to be able to do this kind of problem on my own in the future that's why I'm asking.
it's wrong..
Ok. Then what is the correct answer and how do you get it?
@Shiree19 q + 12 - 2 (q - 22 ) > 0 simplify both sides -q + 56 > 0 subtract 56 from both sides -q + 56 - 56 > 0 - 56 - q > - 56 divide both sides by negative 1 -q/-1 > -56/-1 and you get q < 56 for the answer
@cutelilcigarette Okay. (this will sound like I'm an idiot) But how did you simplify the left side?
\[q+12-2(q-22)>0 first you multiple -2 by q then you multiply -2 by -22 then subtract 44 from 0 then subtract 12 from 0 then you then you take -2q and add 1q so that makes a -1q so then you -1q and devide by -56\]
ok. So I do \[-2 \times q = -2q\] then I do \[-2q \times 22 = -44q\] than I do \[-44 - 12 = -56\] So that's -q + 56?
Is that right? How do you get a negative q?
-2q +1q
oh ok. Thanks so much!
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