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Mathematics 8 Online
OpenStudy (anonymous):

If vector {u} = <-5,-5,5>, vector {v} =<0,-1,1>, and vector {w} =<4,-1,2>. Then what is the answer to this operation? ((vector {w} dot vector {w}) vector {u} ) dot vector {u} =

OpenStudy (amistre64):

youre just going to have to run the dots ....

OpenStudy (amistre64):

u v and w are find names for vectors .. no need to keep stating that they are vectors each time

OpenStudy (amistre64):

in general k(a,b) . j(x,y) = kajx + kbjy = kj (ax+by)

OpenStudy (anonymous):

You lost me cause usually a dot product of one vector onto itself is ||w||^2 which in this case I calculated as sqrt(21). And then you would multiply that result by the u twice. This is my understanding of the problem. But I just can't get the right final answer.

OpenStudy (kainui):

Why did you take the square root of 21? That would be ||w|| not ||w||^2 which is what you're trying to calculate.

OpenStudy (amistre64):

w.w is a scalar u.uis a scalar (w.w)u . u = w.w * u.u

OpenStudy (amistre64):

when we dot a vector to itself: a short cut is simply square the entries, and add them up

OpenStudy (anonymous):

okay. thanks.

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