Question

f(x)=x^2-8x+1

Answer 1

Awesome.

Answer 2

What do you need to do?

Answer 3

Find the x and y intercept

Answer 4

at x =0

f(0)=(0)^2-8(0)+1
f(0) = 1

Answer 5

So, the x intercept is 0, correct?

Answer 6

1 my bad

Answer 7

1 yes

Answer 8

Okay, so what about the y intercept? I don't get how to find that.

Answer 9

f(x)=y=x^2-8x+1
f(x)=x^2-8x+1

so at y = 0

y=x^2-8x+1
0=x^2-8x+1

a = 1
b = -8
c = 1

using quadratic equations
\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a } = \frac{ -(-8) \pm \sqrt{(-8)^2 - 4*1*1}}{ 2*1 } = \frac{ 8 \pm \sqrt{64-4} }{ 2 }\]
\[x = \frac{ 8 \pm \sqrt{60} }{ 2 } = \frac{ 8 \pm 2\sqrt{15}}{ 2 } = 4 \pm \sqrt{15}\]
So
\[x = 4-\sqrt{15}\]
or
\[x = 4 +\sqrt{15}\]